session.masteringchemistry.com Chemistry Primer Untitled mstyPmmer ± Basic Stoic

Question

session.masteringchemistry.com Chemistry Primer Untitled mstyPmmer ± Basic Stoichiometry: Combining Skills t Basic Stoichiometry: Combining Skills This is the most difficult exercise in the digital primer. You must balance an equation, convert to moles, and make a stoichiometric calculation. Part A Balance the following chemical equation, then swnt the folowing question CsHm(g) + 02(g) CO2(g) + H20(g) How many grams of oxygen are required to react with 10.0 grams of octane (C, His) in the combustion of octane in gasoline? Express the mass in grams to one decimal place. Hints g O2 Submit My Answers Give Up

Explanation / Answer

Molar mass of C8H18 = 8*MM(C) + 18*MM(H)

= 8*12.01 + 18*1.008

= 114.224 g/mol

mass of C8H18 = 10 g

mol of C8H18 = (mass)/(molar mass)

= 10/114.224

= 0.0875 mol

we have the Balanced chemical equation as:

2 C8H18 + 25 O2 ---> 18 H2O + 16 CO2

From balanced chemical reaction, we see that

when 2 mol of C8H18 reacts, 25 mol of O2 is reacted

mol of O2 reacting = (25/2)* moles of C8H18

= (25/2)*0.0875

= 1.0943 mol

Molar mass of O2 = 32 g/mol

mass of O2 = number of mol * molar mass

= 1.0943*32

= 35.0 g

Answer: 35.0 g

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