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PCl5 <---> PCl3 + Cl2 Phosphorus pentachloride is injected into a container unti

ID: 694034 • Letter: P

Question

PCl5 <---> PCl3 + Cl2
Phosphorus pentachloride is injected into a container until the initial pressure is 0.82atm. At equilibrium, the total pressure in the container is 1.2atm. Determine the partial pressure of each gas at equilibrium and calculate value of Kp PCl5 <---> PCl3 + Cl2
Phosphorus pentachloride is injected into a container until the initial pressure is 0.82atm. At equilibrium, the total pressure in the container is 1.2atm. Determine the partial pressure of each gas at equilibrium and calculate value of Kp
Phosphorus pentachloride is injected into a container until the initial pressure is 0.82atm. At equilibrium, the total pressure in the container is 1.2atm. Determine the partial pressure of each gas at equilibrium and calculate value of Kp

Explanation / Answer

the reaction is PCl5(g)---->PCl3(g)+Cl2(g)

initial pressure of PCl5= 0.82 atm, let x= drop in pressure of PCl5 to reach equilibrium

at equilibrium, PPCl5= 0.82-x, PPCl3= x and PCl2=x

where P represents the partial pressure

total pressure at equilibrium= sum of partial pressures = 0.82-x+x+x=1.2

x= 1.2-0.82= 0.38 atm

at Equilibrium, PPCl5= 0.82-0.38= 0.44 atm, PPCl3= PCl2=0.38 atm

Kp for the reaction = PCl2*PPCl3/PPCl5= 0.38*0.38/0.44= 0.33

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