LIB-3E-14 35% 12/07/17 0 This is a Numeric Entry question/ It is worth 1 point/

Question

LIB-3E-14 35% 12/07/17 0 This is a Numeric Entry question/ It is worth 1 point/ You have unlimited attempts/There is no attempt penality a See page 440 04 Question point) Unrus is much larger than Earth, with a surface area of The acceleration due to gravity is similar to that on Earth 10 10smawith an atmosphere of low density gases: 82.5% Ha 1 S2% He and 230%4 8.70m/s2 yet the atmospheric pressure on Uranus is estimated to exceed 1.00x10*Pa v 1st attempt 1 SeePeriodic Table ) See Hint What is the mass of the atmosphere on Uranus? ko 043> ader

Explanation / Answer

Question 4:

Presssrue = Force/area

area = 8.1X1015 m2

Force= mass* accleration due to gravity

Pressure= 1*108 Pa= 1*108 N/m2= mass*8.7/8.1*1015

mass of uranus= 1*108*8.1*1015/8.7=9.3*1022 Kg

Question 6:

Apply

P1V1 = P2V2

substitute data

90 mbar = 90*10^-3 bar

then

1 atm = 1.01325 bar

44*1.01325 = (90*10^-3)(V2)

V2 = 44*1.01325 /(90*10^-3)

V = 495.36L

it expands almost 10 times

Question 7:

we have:

P = 2.2 atm

V = 16.1 L

T = 27.1 oC

= (27.1+273) K

= 300.1 K

find number of moles using:

P * V = n*R*T

2.2 atm * 16.1 L = n * 0.08206 atm.L/mol.K * 300.1 K

n = 0.143 mol

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