06 Question (1 point) See page 443 The severity of a tropical storm is related t
ID: 695265 • Letter: 0
Question
06 Question (1 point) See page 443 The severity of a tropical storm is related to the depressed atmospheric pressure at its center. Shown below is a photograph of Typhoon Odessa taken from the space shuttle Discovery in August 1985, when the maximum winds of the storm were about 90 mi/hr and the pressure was 40.0 mbar lower at the center than normal atmospheric pressure. In contrast, the central pressure of Hurricane Andrew was 90.0 mbar lower than its surroundings when it hit south Florida with winds as high as 165 mi/hr. 1st attempt 06:13 > 12 OF 13 QUESTIONS COMPLETED SUBMIT ANSWERExplanation / Answer
We know that
1 atm = 1.01325 bar.
The pressure at the center of the typhoon is 40 mbar lower than the pressure at the edge; hence, the pressure at the center of the typhoon is (1 bar – 40 mbar) = [(1 bar)*(1000 mbar/1 bar) – 40 mbar] = 960 mbar = (960 mbar)*(1 bar/1000 mbar) = 0.96 bar = (0.96 bar)*(1 atm/1.01325 mbar) = 0.94745 atm.
The volume of the balloon at the edge of the typhoon is 44.0 L; we are required to find the volume of the same balloon at the center of the typhoon. Assuming that the gas inside the balloon is an ideal gas and the volume inside the balloon is occupied completely by the gas, we can write the ideal gas law as
P1*V1 = P2*V2 where P1 = 1 atm; V1 = 44.0 L and P2 = 0.94745 atm.
Plug in values
(1.0 atm)*(44.0 L) = (0.94745 atm)*V2
=====> V2 = (1.0 atm)*(44.0 L)/(0.94745 atm) = 46.4404 L 46.44 L (correct to 2 decimal places).
The volume of the weather balloon at the center of the typhoon is 46.44 L (ans).
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.