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23: 1. Which of the following will favor enol formation in the equilibrium betwe

ID: 695397 • Letter: 2

Question

23:

1. Which of the following will favor enol formation in the equilibrium between the compounds shown their related enols? (23.2)

2. Which of the labeled H atoms is most acidic?

3 . Which of the following will form enolates in small equilibrium amounts (the equilibrium favors the starting materials) when treated with NaOCH 2 CH 3 ? Choose all that apply. (23 .3)

4 . Which of the following will form enolates in stoichiometric or near stoichiometric amounts (the equilibrium heavily favors enolate formation) when treated with NaOCH 2 CH 3 ? Choose all that apply. (23.3)

5 . Which of the following will form enol ates in stoichiometric or near stoichiometric amounts (the equilibrium heavily favors enolate formation) when treated with LDA? Choose all that apply. (23.3)

1. Which of the following will favor enol formation in the equilibrium between the compounds shown their related enols? (23.2) 2. Which of the labeled H atoms is most acidic? O O H(c) H(a) H(b) H(d) 3. Which of the following will form enolates in small equilibrium amounts (the equilibrium favors the starting materials) when treated with NaOCH2CH3? Choose all that apply. (23.3) 4. Which of the following will form enolates in stoichiometric or near stoichiometric amounts (the equilibrium heavily favors enolate formation) when treated with NaOCH2CH3? Choose all that apply. (23.3) 5. Which of the following will form enolates in stoichiometric or near stoichiometric amounts (the equilibrium heavily favors enolate formation) when treated with LDA? Choose all that apply. (23.3)

Explanation / Answer

Question no 1

The compound (A) contains two carbonyl group separated by CH2. In such a compound where two carbonyl group are separated by a CH2 the enol form of this compound is more than its ketonic form because the enol is stabilised by chelation.

Hence option (A) is correct.

Question no 2

H(b) is more acidic because the H present on the CH2 :which is between two carbonyl groups is always acidic.

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