. How many moles of P, will form when 1 mole of Ca(POJ, reacts with 3 moles SiO,
ID: 695832 • Letter: #
Question
. How many moles of P, will form when 1 mole of Ca(POJ, reacts with 3 moles SiO, and 2 moles C (A) 6 mol P (C) 05 mol P. (B) 1 mol P D) 02 mol P 22. How many carbon stoms are Molar massmo 3007 found in 10.0 g of C,H.? (A) 361 x 10 atoms (B)4.01 x 10 atoms (C) 2.0t x 10 atoms (D 1.00 x 10 atoms 3. A 26.1 ml sample of a solution is diluted to a final volume of 100.0 mL with a concentration of 0.150 M What was the concentration of the original solution? (A) 235 M (C) 0.575 M (B) 1.74 M (D) 0425 M 24. Identify the oxidizing agent and the reducing agent. Oxidizing Agent (A) C, (B) Fe (C) Fe (D) FeCl, Reducing Agent Fe Cl, FeCl, Cl,Explanation / Answer
(21)
In this reaction, C is the limiting reagent because it is present in less amount than required.
10 moles of C produce 1 mole of P4.
So, Moles of P4 produced by 2 moles of C = 0.2 moles P4
(22)
Moles of ethane = Mass/MW = 10/30.07 = 0.332
1 mole ethane has 2 moles of C.
So, moles of C = 2*0.332 = 0.664
Number of C-atoms = 0.664*6.023*1023 = 4.01*1023 atoms
(23)
Dilution factor, d = 100/26.1 = 3.83
Original conc = New conc*d = 0.150*3.83 = 0.575 M
(24)
In this reaction, oxidation number of Fe increases from 0 to +3, which means it is oxidized.
So,
Fe is the reducing agent and Cl2 is the oxidizing agent.
Hope this helps !
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.