Circle one best answer for each multiple choice. (4 pt each) 1. Lead(II) chlorid
ID: 695868 • Letter: C
Question
Circle one best answer for each multiple choice. (4 pt each) 1. Lead(II) chloride, PbCla, is most soluble in a) H-O, b) NaCI, c) Pb(NO,h. d) HNO 2. In electrolysis of water, 2H2O(I) 2H2(g) + Odg). , is produced at a) anode(+), b) anode(-), c) cathode(+), d) cathode-) The cell reaction of fuel cell (a voltaic cell) is 2H2(g) + Odg) 2H0(I). Oxygen electrode acts as a) anode(+), b) anode(), c) cathode(+), d) cathode(-). 4. What reaction order is radioactive decay? a) zero, b) first, c) second, d) third 5. By what process does thorium-230 to radium-226? a) a-emission, b) B-emission. c) y-emission, d) 6. What is mass number of positron? a) 0, b) 1, c) 2, d)3. 7. Calculate molar solubility of PbClh (Kp-1.7x10) in position-emission. [15 pt a) Water b) 0.010 M KCI. Given redox reaction, Fe"(aq) + Mnodaq) Mn2-(aq) + Feraq) in acidic solution a) 8. [15 pt] Balance the equation. b) Which reactant is oxidized? c) Which reactant is oxidizing agent?Explanation / Answer
1. Lead Chloride is not soluble in any of acids. Lead chloride is neither soluble in Sodium Chloride because of the common ion of Chloride nor soluble in Lead nitrate because of common ion of lead. Lead chloride is most soluble in hot water.
2. 2H+ + 2e- ---> H2. Reaction at Cathode
Reaction at Anode 2H2O --> O2 + 4H+ + 4e-
Thus, oxygen is produced at positively charged Anode
3. Anode side
2H2 --> 4H+ + 4e-
Cathode side
O2 + 4H+ + 4e- --> 2H2O
Net reaction
2H2 + O2 --> 2H2O
4. The radioactive decay is first order reaction in nature.
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