The following questions apply to separation of a solution containing pentanol (F
ID: 696322 • Letter: T
Question
The following questions apply to separation of a solution containing pentanol (FM 88.15) and 2,3-dimethyl-2- butanol (FM102.17). Pentanol is the internal standard. (a) Separation of a standard solution containing 223 mg of pentanol and 233 mg of 2,3-dimethyl-2-butanol in 10.0 ml of solution led to a pentanol:2,3-dimethyl-2-butanol relative peak area ratio of 0.921:1.00. Calculate the response factor, F, for 2,3-dimethyl-2-butanol. Number 1.2001 (b) Calculate the areas for pentanol and 2,3-dimethyl-2-butanol gas chromatogram peaks in an unknown. For pentanol, the peak height was 49.6 mm and the width at half-height was 2.8 mm. For 2,3-dimethyl-2- butanol, the peak height was 85.8 mm and the width at half-height was 2.1 mm. Assume each peak to be a Gaussian. Incorrect. In part (b), calculate the area of each Gaussian peak Number using the equation Pentanol: 138.83 m mº Area = 1.064 X peak height X w.12 Number where w1/2 is the width at half-height. mm? 2,3-Dimethyl-2-butanol: 191.71 (Scroll down for more questions.) (c) If the concentration of nentanal in the Linkro...--l..r ---/LI...-- Ann -- ...-...-- the nn an" am ei... e. 4. TA. I. EExplanation / Answer
b)
Area of Gaussian peak = 1.064 x peak height x w1/2
Area of pentanol = 1.064 x 49.6 x 2.8
= 147.8 mm2
Area of pentanol = 148 mm2
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