I\'m missing the stuff blanks. but if i have anything wrong please let me know.
ID: 696778 • Letter: I
Question
I'm missing the stuff blanks. but if i have anything wrong please let me know. thanks in advance
Data: Experiment 10; Crystal Structures Make sure to include all tables in the Results section if your Lab Report. Table 10.1 (You will be calcuiating the radil of sodium and copper during the course of the lab. Da not enter numbers from the internet! (these will vary) I should see the number that you calculated) Atom Molar Mass (g/mol) Atomic Radius (nm) Ionic Radius (nm) Na 22.99 Cu63.55 Cl Cs Zn65.38 0.185 nm 0.128 nm 0.099 0.262 0.133 0.104 0.231 0.133 0.114 0.095 0.096 0.181 0.169 0.074 0.184 0.133 0.216 0.195 0.147 35.45 132.9 32.06 39.10 126.9 79.90 T 204.4 1. Simple Cubic Structure (F'ill in the table with the mathematical expressions for each -some of these will need to be calculated to be expressed in the form asked for.) Table 10.2 Simple Cubic Structure Volume of unit cell in terms of s Number of atoms per unit cell Radius, r, of atom in terms ofs volume of atom in terms of s (V-4/3 r) Volume of atom/volume of cell (43) (S/2)-(rS)3/6 /6= 0.5236 Body Centered Cube Structure Volume of unit cell in terms of s Number of atoms per unit cell Radius, r, of atom in terms of s volume of atom! in terms of s (V = 4/3 r) Volume of atom/volume of cell V3TS/ 16 0.68Explanation / Answer
Answer
4. NaCl
The number of Cl-ions in the unit cell of FCC = 4
Explanation:
In NaCl, Cl- ions hace FCC arrangement, where Cl- are present at the corners and at the center of each face. As, there are 8 corners and 6 faces, an atom present at the corner will be shared by 8 unit cell. therefore, the contribution of each atom at the corner is 1/8. An atom at the face will be shared by 2 unit cells. Hence, each atom on face will be contributing 1/2. There are 6 faces.
No. of Cl- ions = 8*1/8 +6 * 1/2 = 4
No of Na ions on the edges of cell = 1/4 at each edge shared by 12 edges = 1/4*12 = 3
(Each edge of the cube is shared by four other cubes, so there is 1/4 of a sodium ion at each edge. There are 12 edges in the cell).
No of Na ions in the center of cell = 1 shared by none = 1.
Total Number of Na ions = 4
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