23. What is the correct Lewis electron-dot formula for CO? 24. What is the molec

Question

23. What is the correct Lewis electron-dot formula for CO? 24. What is the molecular geometry and electron-group geometry of? PCh 25. What are the approximate CCO angle and molecular geometry in acetone, HicccH, 2 26. What is the bond angle in NH4? 27. What is the molecular geometry of the nitrite ion, NO, ? 28. The molecular geometry of the CHs ion is 29. What is the molecular gcometry and electron-group geometry of the bromate ion, BrOs ? 30. What is the electron-group geometry of CIF? 31. Calculate the number of moles of O2 required to react with phosphorus to produce 4.76 g of P.0s. (Molar mass P4Os -219.9 g/mol) 32. Lead oxide decomposes into lead metal and oxygen gas according to the equation below. How many moles of lead will form when 4.6 moles of lead oxide decomposes? 2PbO(s) 2PD(s) + O2(g) 33. When 10.0 g CaHs and 30.0 g O2 react to form CO2 and H20, how many grams of water are formed? 34. How many atoms of carbon are there in 0.0476 mol of procaine, CsHpoN2O2, a "pain killer used by dentists? 35. The reaction of H2SOs with NaOH is represented by the equation H2so.(aq) 2NaOH(aq) Naso.(aq) 2H2O(1) + + What volume of 1.4 M H.So, is required to neutralize 6.55 mL of 0.111 M NaOH?

Explanation / Answer

Question 32

Balanced equation:
2 PbO = 2 Pb + O2
Reaction type: decomposition

The same amount of Pb will form what amount has reacted . Hence 4.6 mole of PbO will react to 4.6 moles of Pb.

Question 33

Balanced equation:
2 C2H6 + 7 O2 = 4 CO2 + 6 H2O
Reaction type: combustion

10 g of C2H6 = 10 / 30.06 = 0.3325 Moles

30 g of O2 = 30 /32 =  0.9375 Moles

Limiting reagent is O2  

Moles of water formed =  0.8036 Moles

Mass of water formed = 0.8036 x 18 =  14.48 gm

Question 34

One Mole of Procaine will have avogadro number of molecules (6.022140857 × 10 23.)

One molecule of Procaine will have 13 molecules of 13C.

Hence number carbon atoms in 0.0476 mole = 0.0476 x 6.023 x 1023 x 13 = 3.727 x1023 Moelcules

Question 35

Moles of NaOH reacted = 6.55 x 0.111 / 1000 = 0.00072705 Moles

Moles of H2SO4 needed =  0.000363525 Moles

Volume of H2SO4 needed =  0.000363525 x 1000 / 1.4 = 0.2597 ml

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