8. O2 can be converted to O, in the presence of an electrical spark according to

Question

8. O2 can be converted to O, in the presence of an electrical spark according to the equation below The type of change taking place is a (A) chemical change because a new substance is formed (B) physical change because no new substance is 12. formed. C) chemical change because O2 and O, are both elemental forms of oxygen. (D) physical change because the element is the same ansd only in a new form. 9. A gaseous mixture at a total pressure of 6.00 atm contains equal molar amounts of H constant temperature, more He gas mixture until the total pressure is 8 statement is correct about the final gas mixture? He, Ar and Ne. A is added to the .00 atm. Which (A) The partial pressure of Ne has become equal to the (B) (C) (D) partial pressure of He. There are more moles of Ar compared to He. The partial pressure of Ar has decreased. The partial pressure of He has doubled. 50 10. Which metal (copper or gold) will float if placed in4 gold mercury at room temperature? 30 20 10 copper volume/ml (A) copper because it has a density less than that of (B) copper because it has a density greater than that of (C) gold because it has a density less than that of (D) gold because it has a density greater than that of mercury mercury mercury mercury

Explanation / Answer

8)

this is a chemical change because new chemical compound is formed

Answer: A

9)

initially when pressure was 6.00 atm:

p(He) = 2.00 atm

p(Ne) = 2.00 atm

p(Ar) = 2.00 atm

when now pressure becomes 8.00 atm by adding He.

This increase in pressure is due to helium

So,

p(He) = 4.00 atm

p(Ne) = 2.00 atm

p(Ar) = 2.00 atm

Answer: D

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