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Connect Sign In or Sign Up |Ch >x A sample of carbon me of carbon https://newconnect. mheducation.com/flow/connect.html ive: Gases and the Kinetic-Molecular The. Saved O You received partial credit in the previous attempt What is the effect of each of the following on the volume of 1 mol of an ideal gas? (a) The pressure changes from 760 torr to 202 kPa, and the temperature changes from 37°C to 155 K. O The volume increases by a factor of 2. O The volume increases by a factor of4 O The volume decreases by a factor of 2. The volume decreases by a factor of 4 O The volume remains the same (b) The temperature changes from 305 K to 32°C, and the pressure changes from 2 atm to 101 kPa. O The volume increases by a factor of 2 o The volume increases by a factor of 4. The volume decreases bv a factor of 2 The volume decreases by a factor of 4 K Prex 5 of 27 Next >

Explanation / Answer

(a).

Combined gas law is expressed as

P1V1 / T1 = P2V2 / T2

Here,
P1 = 760 torr
P2 = 202 kPa = 202000 Pa = 0.0075 x 202000 torr = 1515 torr
T1 = 37 oC = (273 + 37) K = 310 K
T2 = 155 K

Substituting the values in the combined gas law equation, we get

(760 torr) V1 / (310 K) = (1515 torr) V2 / (155 K)

V1 = [ (1515 torr) x (310 K)] / [ (155 K) x (760 torr)] x V2

V1 = 4 x V2

V2 = (1/4) V1

So the volume decreases by a factor 4.

(b)

Combined gas law is expressed as

P1V1 / T1 = P2V2 / T2

Here,
T1 = 305 K
T2 = 32 oC = (273 + 32) K = 305 K
P1 = 2 atm
P2 = 101 kPa = 101000 Pa = 101000 x (9.8692 x 10-6) atm = 1 atm

Substituting the values in the combined gas law equation, we get

(2 atm) V1 / (305 K) = (1 atm) V2 / (305 K)

V1 = [ (1 atm) x (305 K)] / [ (305 K) x (2 atm)] x V2

V1 = 0.5 x V2

V2 = 2 V1

So the volume increases by a factor 2.

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