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Question

me File Edit View History Bookmarks People Window Help 71% co wed 3:24 PM Da MasteringChemistry: practice titration https://se try.com/myct/itemView?offset-next&assignmentProblemID-94126572; practice,titration ±Neutralizing an Acid Spill Resources previous | 4 of 4 return to assign ± Neutralizing an Acid Spill Part A A tanker truck carrying 3.02*103 kg of concentrated sulfuric acid solution tips over and spills its load. The sulfuric acid solution is 95.0% H2SO4 by mass and has a density of 1.84 g/mL Sodium carbonate (Na2 CO,) is used to neutralize the sulfuric acid spill. How many kilograms of sodium carbonate must be added to neutralize 3.02*103 kg of sulfuric acid solution? Express your answer with the appropriate units Hints Value Units Submit My Answers Give Up Continue

Explanation / Answer

molar mass of H2SO4 = 98 g/mol
= (98*10^-3) kg/mol
number of mol of H2SO4 = (given mass)/(molar mass)
= (3.02*10^3)/(98*10^-3)
= (3.08*10^4) mole

reaction
Na2CO3 + H2SO4 --> Na2SO4 + H2CO3
according to reaction
number of mol of Na2CO3 required = number of mol of H2SO4
= (3.08*10^4) mole

molar mass of Na2CO3 = 106 g/mol
= 0.106 kg/mol
mass of Na2CO3 = (number of mol of Na2CO3 required)*(molar mass of Na2CO3)
= (3.08*10^4)*0.106
= (3.26*10^3) kg

Answer : (3.26*10^3) kg