1. 70 grams of CaCl2 is dissolved in water to give 500 mL of solution. Calculate
ID: 698583 • Letter: 1
Question
1. 70 grams of CaCl2 is dissolved in water to give 500 mL of solution. Calculate the Molarity of the solution
2. When the gases are at the same temperature 7 liters of H2 gas reacted with 7 liters of Cl2 to give HCl. What is the theoretical yield of HCl in liters?
3. Using the ideal gas law, calculate the pressure of Neon when 60 grams of Ne at 27o C has a volume of 90 liters.
4. For the freezing point lowering of an aqueous sucrose solutions what are the terms in the equation T freezing = imKf
5. How many grams of CaCl2 are in 3.2 L of 1.8 M CaCl2 aqueous solution?
Explanation / Answer
1)
Molar mass of CaCl2 = 1*MM(Ca) + 2*MM(Cl)
= 1*40.08 + 2*35.45
= 110.98 g/mol
mass of CaCl2 = 70 g
we have below equation to be used:
number of mol of CaCl2,
n = mass of CaCl2/molar mass of CaCl2
=(70.0 g)/(110.98 g/mol)
= 0.6307 mol
volume , V = 500 mL
= 0.5 L
we have below equation to be used:
Molarity,
M = number of mol / volume in L
= 0.6307/0.5
= 1.26 M
Answer: 1.26 M
Only 1 question at a time please
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.