I need help with problems 12/13 since they play off each other. Question 13 refe
ID: 699217 • Letter: I
Question
I need help with problems 12/13 since they play off each other. Question 13 references question 7-4 which I have included a picture of as well as my answer for for reference.
Explanation / Answer
12.
CH4 + 2 O2 --> CO2 + 2 H2O : 2 moles of O2
H2 + ½ O2 --> H2O : ½ mol of O2
Ratio of heat released = 2 / ½ = 4
13.
a)
Using thermochemical information of 12,
Let amount of heat by H2 combustion = X
Amount of heat by H2 combustion / g of H2 = X / 2
Amount of heat by CH4 combustion = 4 X
Amount of heat by CH4 combustion / g of CH4 = 4 X / 16 = X / 4
Heat released by H2 combustion / g of H2 > Heat released by CH4 combustion / g of CH4
X / 2 > X / 4
Therefore, fuel H2 is superior on weight basis.
b)
From question 12, Heat of combustion of CH4 /mol > Heat of combustion of H2 /mol
Using actual heat of combustion of fuels,
Heat of combustion of H2 = 286 kJ/mol
Heat of combustion of CH4 = 889 kJ/mol
Heat of combustion of CH4 /mol > Heat of combustion of H2 /mol
Therefore, fuel CH4 is superior on molar or volume basis
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.