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Lineweaver- burk plot is 1/V= (KM/Vmax)*1/S +1/Vmax so a plot of 1/V vs 1/S give

ID: 699489 • Letter: L

Question

Lineweaver- burk plot is 1/V= (KM/Vmax)*1/S +1/Vmax

so a plot of 1/V vs 1/S gives straight line whose slope is KM/Vmax and intercept of 1/Vmax

in case of inhibition, KM will be replaced with Kmapp and Vmax will be replaced with Vmaxapp

so a plot of 1/V vs 1/S along with data points is shown below.

from the plot, the absence of inhibitor, 1/Vmax= intercept = 0.015, Vmax= 1/0.015=66.67 mM/min

KM/Vmax= slope =0.009, Km= 0.009*66.67=0.6 mM

since in the presence of inhibitor also, Vmaxapp= 1/0.015=66.67 mM/min same as that of no inhibitor, this is the case of competitive inhibition where the inhibitor competes with the enzyme for binding to the substrate.

Explanation / Answer

Please help me answer! thank you!

Prostaglandins are a class of eicosanoids, fatty acid derivatives with a variety of extremely potent actions on vertebrate tissues. They are responsible for producing fever and inflammation and its associated pain Prostaglandins are derived from the 20-carbon fatty acid arachidonic acid in a reaction catalyzed by the enzyme prostaglandin endoperoxide synthase. This enzyme, a cyclooxygenase, uses oxygen to convert arachidonic acid to PGG2, the immediate precursor of many different prostaglandins (al The kinetic data given in the table are for the Rate of formation of PGG2 reaction catalyzed by a mutant of prostaglandinArachidonic acid Rate of formation endoperoxide synthase. Focusing here on the first two columns, determine the Vmax and Km of the enzyme (mM) 0.295 0.354 0.531 0.885 2.07 of PGG2 (mWmin) 21.0 23.6 29.8 37.8 49.0 with 10 mg/mL (mWmin) 13.1 15.1 20.3 27.8 40.9 Number mM/ min max Number K, In
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