Ans - A oxidation number for each element In H2O2 (aq) Oxidation number of H = +

Question

Ans - A

oxidation number for each element

In H2O2 (aq)

Oxidation number of H = +1,

O = - 1 ( O is in peroxide form)

In ClO2 (aq)

Cl =+4

O = - 2

In ClO-2 (aq)

Cl = +3

O = - 2
O2 (g) O = 0.

Change in oxidation number

Cl = from 4+ to 3+

O = from -1 to 0.

Cl is reduced

O is oxidized.

Balance the chlorine atoms on both sides

H2O2 (aq) + 2 ClO2 (aq) ---> 2 ClO2- (aq) + O2 (g)

Balance hydrogen atoms by adding OH- ions
H2O2 (aq) + 2 ClO2 (aq) + 2 OH- (aq) ---> 2 ClO2- (aq) + O2 (g) + 2 H2O (l)

balance the charges
Cl2 (g) + 2 OH- (aq) ---> Cl- (aq) + ClO- (aq)

Balance the oxygen atoms by adding H2O

Cl2 (g) + 2 OH- (aq) ---> Cl- (aq) + ClO- (aq) + H2O (l)

Explanation / Answer

Part A

H2O2(aq)+ClO2(aq)ClO2(aq)+O2(g)

Express your answer as a chemical equation. Identify all of the phases in your answer. identify charges and include electrons

PartB

Al(s)+MnO4(aq)MnO2(s)+Al(OH)4(aq)

Express your answer as a chemical equation. Identify all of the phases in your answer. identify charges and include electrons?

Part C

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