a ) N2 + 3H2 ------------------------> 2 NH3 1 2 2 400 100 pressures ratio of N2
ID: 699538 • Letter: A
Question
a )
N2 + 3H2 ------------------------> 2 NH3
1 2 2
400 100
pressures ratio of N2 =400 /1 = 400
pressures ratio of H2 = 100 / 2 = 50
pressures ratio of H2 is less than that of N2. so H2 is the limiting reagent
b)
H2 pressure = 0.0 torr
N2 pressure left = 400 - 100 x 1 / 2 = 350 torr
N2 pressure = 350 torr
NH3 pressure = 2 torr H2 -----------------> 2 torr NH3
100 torr H2 -----------------> 100 torr NH3
pressure of NH3 = 100 torr
total pressure = 350 + 100
= 450 torr
Explanation / Answer
(15 points) We mix 400. torr of H2 and 100, torr of N2 in a 2.00 liter flask at 400·°C Assume that the following reaction occurs and goes to completion: N2(g) + 3H2(g) 2NH3(g) (a) What is the limiting reagent? Show by calculation. (b) Afer the reaction has been completed, what pressure of each gas is presenti the flask and what is the total pressure?
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