1 ml of HCl is diluted to 10 ml (check the above and then proceed accordingly) m
ID: 699872 • Letter: 1
Question
1 ml of HCl is diluted to 10 ml
(check the above and then proceed accordingly)
molarity of NaOH (titrant) = 0.09198 M
Trial 1, volume of NaOH used = 27.80 ml
moles NaOH used = moles HCl present = 0.09198 M x 27.80 ml = 2.557044 mmol
molarity of diluted HCl solution = 2.557044 mmol/10 ml = 0.256 M
molarity of undiluted HCl solution = 0.256 M x 10 ml/1 ml = 2.56 M
Trial 2, volume of NaOH used = 25.00 ml
moles NaOH used = moles HCl present = 0.09198 M x 25.0 ml = 2.2995 mmol
molarity of diluted HCl solution = 2.2995 mmol/10 ml = 0.23 M
molarity of undiluted HCl solution = 0.23 M x 10 ml/1 ml = 2.30 M
Trial 3, volume of NaOH used = 25.20 ml
moles NaOH used = moles HCl present = 0.09198 M x 25.20 ml = 2.318 mmol
molarity of diluted HCl solution = 2.318 mmol/10 ml = 0.232 M
molarity of undiluted HCl solution = 0.232 M x 10 ml/1 ml = 2.32 M
Average molarity of undiluted HCl solution = 2.39 M
Explanation / Answer
Data Sheet Ill. Titrating the Diluted Acid Solution molarity of NaOH solution, M sample number of HCI solution determination final buret reading, ml. initial buret reading, mL volume of titrant used, ml 251-0252L volume of titrant used, L molarity of diluted HCI solution, M molarity of undiluted HCI solution, M mean molarity of undiluted HCI XIO solution, M o0 ok d. ct
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