1) mass of F / mass of Mg = same for all samples mass of F in sample 2 / mass of
ID: 699899 • Letter: 1
Question
1)
mass of F / mass of Mg = same for all samples
mass of F in sample 2 / mass of Mg in sample 2 = mass of F in sample 1 / mass of Mg in sample 1
mass of F in sample 2 / 1.36 = 2.57 / 1.65
mass of F in sample 2 = 2.118 kg
mass of fluorine in second sample = 2.12 x 10^3 g
2)
since there are two H atoms in H2O and 3 hydrogen atoms in NH3
total no of Hyderogens = 2 x number of H2O + 3 x number of NH3
= 2 x 3.2 x 10^25 + 3 x 8.30 x 10^24
total no of Hyderogens = 8.89 x 10^25
Explanation / Answer
Upon decomposition, one sample of magnesium fluoride produced 1.65 kg of magnesium and 2.57 kg of fluorine. A second sample produced 1.36 kg of magnesium.
How much fluorine (in grams) did the second sample produce?
A solution of ammonia and water contains 3.20×1025 water molecules and 8.30×1024 ammonia molecules. How many total hydrogen atoms are in this solution?
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