First convert moles to mass in grams by multiplying with molar mass of isopropyl

Question

First convert moles to mass in grams by multiplying with molar mass of isopropyl alcohol

2.0 mol x 60.0 g/mol = 120 g

Part-A: Melting:

Q = mass in grams x heat of fusion = 120 g x 21.4 cal/g = 2568 cal = 2.568 kcal

Answer: 2.568 kcal of heat is required to melt 2.0 mol of isopropyl alcohol.

Part-B: Boiling:

Q = mass in g x heat of vaporization = 120 g x 159 cal/g = 19080 cal = 19.08 kcal

Answer: 19.08 kcal of heat is required to boil 2.0 mol of isopropyl alcohol.

Thank You So Much! Please Rate this answer as you wish.

Explanation / Answer

How much heat in kilocalories is required to melt 2.0 mol of isopropyl alcohol (rubbing alcohol; molar mass = 60.0 g/mol)? The heat of fusion and heat of vaporization of isopropyl alcohol are 21.4 cal/g and 159 cal/g, respectively. Pt. B: How much heat in kilocalories is required to boil 2.0 mol ??

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.