P4O10(s) + 6H2O(l) ----------> 4H3Po4(aq) no of moles of P4O10 = W/G.M.Wt = 15/2
ID: 700328 • Letter: P
Question
P4O10(s) + 6H2O(l) ----------> 4H3Po4(aq)
no of moles of P4O10 = W/G.M.Wt
= 15/283.88 = 0.053moles
no of moles of H2O = W/G.M.Wt
= 15/18 = 0.84 moles
6 moles of H2O react with 1 mole of P4O10
0.84 moles of H2O react with = 1*0.84/6 = 0.14 moles of P4O10
P4O10 is limiting reactant
P4O10(s) + 6H2O(l) ----------> 4H3Po4(aq)
no of moles of P4O10 = W/G.M.Wt
= 15/283.88 = 0.053moles
no of moles of H2O = W/G.M.Wt
= 15/18 = 0.84 moles
6 moles of H2O react with 1 mole of P4O10
0.84 moles of H2O react with = 1*0.84/6 = 0.14 moles of P4O10
P4O10 is limiting reactant
Element % A.Wt Relative number simple ratio simplest ratio
C 74.84 12 74.84/12 = 6.24 6.24/0.8275 = 7.5 7.5*2 = 15
H 11.92 1 11.92/1 = 11.92 11.92/0.8275 = 14.4 14.4*2 = 29
O 13.24 16 13.24/16 = 0.8275 0.8275/0.8275 =1 1*2 = 2
Empirical formula = C15H29O2
Explanation / Answer
(23.8), reacts sipreusly withr (15 02) che equation below student added 15.00 g of POo to 15.00g of water. Determine t the limiting reactant showing your 3a.3 marky Menthol can be used in cough medicines. mass. Determine its empirical formala . The compound contains 74se%C i i 92% H and i 324%hy
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