First calculate the double bond equivalent of the compound C 5 H 13 N. It tells

Question

First calculate the double bond equivalent of the compound C5H13N. It tells the number of multiple bond or rings in the given compound.

D.B.E = No. of C + 1 - (No. of H - No. of N / 2) = 5 +1 - (13-1/2) = 6 - 6 =0 (It means no double and triple bond or ring). It means N is present as amine group.

Now look at NMR spectrum

There are three signals, it means three types of H are present

Peak between 0 - 1.5 ppm is due to H of alkyl group

Peaks between 1.5 - 3 ppm are due CH2NR2

Peak ratio 4:3:6 corresponds that there are three types of hydrogen with 4, 3 and 6 number of hydrogen respectively.

The structure of C5H13N comes out to be

CH3-CH2-N(CH3)-CH2-CH3

Explanation / Answer

Draw the structure of the compound CSH13N from its proton(H) NMR spectrum below. First-order spin-spin splitting rules and equal coupling constants can be asummed. (Detailed analysis of any non-first order portions of the spectrum will not be required.) ntegral ratios to the nearest whole number are (left to right) 1:4:3:6. Use your cursor to read the chemical shift scale. Spin-spin splitting multiplets can be expanded using the "Zoom" and Y-axis expansion(x5 Y) tools. (See information page for details.) Flash Installation and Troubleshooting Used with permission from Aldrich Chemical Co., Inc. Solvent CDCla (impurity at 3.40 ppm) Chemical shift 5 Y ZOOM MEASURE 9.0 7.5 6.0 4.5 3.0 1.5 0.0 Chemical shift, (ppm)

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