Sn(s) ---> Sn2+ + 2e- (Ag+ + e- -----> Ag(s)) x2 2Ag+ + 2e- ----> 2Ag(s) -------

Question

Sn(s) ---> Sn2+ + 2e-

(Ag+ + e- -----> Ag(s)) x2
2Ag+ + 2e- ----> 2Ag(s)
-----------------------------
Sn + 2Ag+ -----> Sn2+ + 2Ag(s)

E°cell=E°+E°

Sn(s) ---> Sn2+ +2e- = +.14

Ag+ + 2e- ---> Ag(s) =+.80

E°cell= 0.94 V

now you can find Ecell

Ecell = E°cell - (RT/nF)ln(Q)

R=8.3145 J(/mol)(K)
T= 25C or 298K
n= 2 (2e-)
F= 96,485 c/mol ( F is a constant)
Q= (.0155)/(1.50)2

Q= products/reactants
you square the domnoinator for Q because in our net cell equation the coiefficent for Ag+ is 2

Ecell= 0.94 - { 8.3145(298)/2(96,485)ln(0.0155/(1.50)2) }

Ecell= 0.94 - {-0.063915}

Ecell = 1.0039 V

Explanation / Answer

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