a) In Half cell B Concentration of Zn2+ decrease Half cell B having more concent

Question

a) In Half cell B Concentration of Zn2+ decrease

Half cell B having more concentration than Half cell A

So, Zn2+ ions in Half cell B will be reduced to Zn(s) and Zn(s) in Half Cell A get oxidized to Zn2+ ions, So that Zn2+ in Both half cell will be equal

Oxidation Half cell (Half Cell A) - Anode

Zn(s) - - - - - - > Zn2+(aq) + 2e

Reduction Half cell ( Half cell B) - Cathode

Zn2+(aq) + 2e - - - - - - > Zn(s)

Cell potential is obtained by newest equation

E = - (0.0592/n)logQ

Q= [Zn2+]low/ [Zn2+]high

n = no of electronic transfer, 2

b) Electrons flow from Half cell A to Half cell B

Explanation / Answer

Concentration cell with Half- cell A containing .1 M Zn2+ and Half cell B containing 1 M Zn2+. a) in which half cell, A or B will the concentration of Zn2+ decrease and why? b) in which direction will the electrons flow in this cell

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.