A number of reactions that take place on the surfaces of catalysts are zero orde

Question

A number of reactions that take place on the surfaces of catalysts are zero order in the reactant. One example is the decomposition of ammonia on hot tungsten. In one experiment, the concentration of ammonia decreased from 21 M to 10 M in 770 s What is the rate constant for the zero-order reaction? Hint: to answer this question you will need to use the integrated rate law of a zero order reaction and substitute the values of [Alo. [A] and t, to find k. Look at lecture 5 notes and think about what the constant of integration 'c is

Explanation / Answer

For zero order reaction

A B

-rA = – d[A]dt = k[A]0

– d[A]dt = k

d[A] = -k dt

Integrating the equation

[A] = -kt + c………………………..eq1

c= integration constant

At time t=0

[A] = [A]0

From eq1

[A]0  = c

Again Eq 1

[A] = -kt + [A]0

This is the equation of zero order reaction

Put the given values and calculate k

10 = - k x 770 + 21

k = 0.0143 M/s

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