A liquid/vapour mixture of water initially has a quality of 0.6. Which of the fo

Question

A liquid/vapour mixture of water initially has a quality of 0.6. Which of the following statements will result in an increase in quality, if the final state remains as a liquid/vapour mixture? Select one: a. Increasing the pressure and decreasing the temperatureoss out b. Increasing the pressure and increasing the temperatureross out c. Decreasing the pressure and decreasing the temperatureoss out d. Decreasing the pressure and increasing the temperatureross out e. Not enough informationross out

Explanation / Answer

Vaporization of any component increases when :

(i) When pressure is reduced at a given temperature or (ii) Temperature is increased.

Increasing the quality of steam water vapour mixture shall result in higher quentity of steam in system. Thus, it corresponds to higher vapourization of water. Therfore, on decreasing pressure & increasing temperature quality of steam shall definitely increase (Part d). However, on decreasing pressure & decreasing the temperature (part c) resultant quality cant be calculated when initial & final pressure/temperature & some other information are known as two opposing effects (decreasing pressure means higher steam quality but decreasing temperature means lower steam quality) are working. Same principle goes for part b on increasing pressure & increasing the temperature, resultant quality can be calculated when initial & final pressure/temperature & some other information are known as two opposing effects (increasing pressure means lower steam quality but increasing temperature means higher steam quality). For part a we can say with certainty that steam quality shall decrese.

Therefore, for Part a : Steam quality shall decrese certainly.

Part b & c : Initial & final steam condition along with some other system information is requred.

Part d: Steam quality shall increase definitely.

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