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Need help from 6-8 please REPORT FOR EXPERIMENT 5 (continued) NAME QUESTIONS AND

ID: 701304 • Letter: N

Question


Need help from 6-8 please REPORT FOR EXPERIMENT 5 (continued) NAME QUESTIONS AND PROBLEMS 1. Why is it important for there to b the metal sample? AT O UI, "to me w 2whdid w reading n in the boiling water? ecause we, woul a ho 3. The water in the beaker gets its heat energy from th hana the water in the calorimeter gets its heat energy from the What is the specifie heat in J/g"C for a metal sample with a mass of 95.6 g which abeorbs 1 J of energy when its temperature increases from 30.0-C to 98.0-C? . What effeet does the initial temperature of the water have on the change in tempera- ture of the water after the hot metal is added? Explain your answer. he metal tnen los hal 1e Res ults of scientific experiments must be reproducible when repeated or they do not mean anything. When results are repeated, the experiment is said to have good preci- sion. When the results agree with a theoretical value they are described as accurate. 6. Which is better, the precision or the accuracy of the experimental s mined for your metal sample? Support your answer with your data. (10k 1 Use the data presented in Table 5.1 to answer questions 7-9 and complete the graph on the next page to show the relationship between the atomic mass and the specific heat of the seven metals listed. Make the graph following the guidelines provided in Study Aid 3 7. a. What is the independent variable? b. What is the dependent variable? 8. In Table 5.1, what is the range of values for atomic mass?

Explanation / Answer

Q= heat of reaction (heat gained = -heat lost)
m= mass
s= specific heat
T= temperature change of metal
you are given that:
Q= 841J absorbed
m= 95.6g
s= WE DONT KNOW
T= (98.0-30.0)°C
lets substitute!
841J= (95.6g)(s)(98.0°C-30.0°C)
lets solve for s. so divide both sides by (98.0°C-30.0°C)(95.6g)
(841)/(68)(95.6) = 0.13J/g°C

5. When hot metal is added into the water then the metal looses its energy into the water and this heat is gained by the water, so the temperature gets increases when hot metal added into it i.e final temperature is greater than initial temperature of water.

6. Accuracy because it tells us how close our value is to the accepted/expected value rather than precision that only describes reproducibilty and closeness of results to One another.

Accuracy refers to the closeness of a measured value to a standard or known value. For example, if in lab you obtain a weight measurement of 3.2 kg for a given substance, but the actual or known weight is 10 kg, then your measurement is not accurate. In this case, your measurement is not close to the known value.

Precision refers to the closeness of two or more measurements to each other. Using the example above, if you weigh a given substance five times, and get 3.2 kg each time, then your measurement is very precise. Precision is independent of accuracy. You can be very precise but inaccurate, as described above. You can also be accurate but imprecise.

For example, if on average, your measurements for a given substance are close to the known value, but the measurements are far from each other, then you have accuracy without precision.A good analogy for understanding accuracy and precision is to imagine a basketball player shooting baskets. If the player shoots with accuracy, his aim will always take the ball close to or into the basket. If the player shoots with precision, his aim will always take the ball to the same location which may or may not be close to the basket. A good player will be both accurate and precise by shooting the ball the same way each time and each time making it in the basket.

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