A protein has a migration time of 7.44 min on a 50.0 cm capillary electrophoresi

Question

A protein has a migration time of 7.44 min on a 50.0 cm capillary electrophoresis system at an applied voltage of 6.50 kV. The detector is located 47.5 cm from the injection port. Assuming that electroosmotic flow is negligible, calculate the migration velocity, unet, and apparent mobility, app, of the protein.

HINT = The net migration velocity, unet, is the sum of the electroosmotic velocity, ueo, and the electrophoretic velocity, uep. Since the electroosmotic flow is negligible, unet = uep. Pay attention to the units of each variable.

unet=? cm/s

app= ? m^2/(V s)

Explanation / Answer

net = eo=+ep

Here the electroosmotic flow is negligible

So net= ep

net=ep= Vep/E=(Ld/tm)/(V/Lt)

(47.5cm)(446.4)/(6500/50)=

Here net=ep= 163cm2/vs

Apparent mobility app=ep+eo

So app=163cm2/vs

Migration velocity of protein

Vep=epE=ep(V/L) =(163 cm2/vs)x((6500v/50cm)=1.25cm/s

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