0 150 CHAPTER 4 Fundametals Methane is burned to form carbon dioxide and water i

Question

0 150 CHAPTER 4 Fundametals Methane is burned to form carbon dioxide and water in a batch reactor: Test Yourself CH4 + 2O2 CO2 + 2H2O (Answers, p. 656) The feed to the reactor and the products obtained are shown in the following flowchart: 40 mol CHs 100 mol CH 250 mol O 130m01 02 60 mol CO2 120 mol H,0 1. How much methane was consumed? What is the fractional conversion of methane? 2. How much oxygen was consumed? What is the fractional conversion of oxygen? 3. Write the extent of reaction equation (4.6-4) for methane, oxygen, and CO2. Use each 4. How many independent molecular species balances can be written? How many 5. Write the following balances and verify that they are all satisfied. The solution of the first equation to determine the extent of reaction, , substituting inlet and outlet values from the flowchart. independent atomic species balances can be written? one is given as an example. (a) Methane. (I = O + C 100 mol CH4 in = 40 mol CH4 out + 60 mol CH4 consumed) (b) Atomic oxygen (O). (c) Molecular oxygen (O2). (d) Water. (e) Atomic hydrogen

Explanation / Answer

1. Methane consumed = Moles of methane in inlet - moles of methane in outlet = 100 - 40 = 60 mol Methane used

2. Oxygen consumed = Moles of oxygen in inlet - moles of oxygen in outlet = 250 - 130 = 120 mol Oxygen used

Fractional conversion = moles consumed/moles at inlet x 100 = 120/250 x 100 = 48% oxygen conversion

3. Conversion of methane = moles consumed/moles at inlet x 100 = its extent of reaction = 60/100 x 100 = 60%

Since conversion of methane > conversion of oxygen, METHANE IS THE LIMITING REAGENT, AND EXTENT OF REACTION IS THE CONVERSION OF THE LIMITING REAGENT

Extent of reaction = 60%

4. Molecular balance equations:

Atomic balance equations: Since there are 3 atoms, we can write equations for all three of them and all will be independent.

5. b) Atomic oxygen: inlet = 250 x 2 = 500; oulet = 2 x 130 + 60 x 2 + 120 = 500 --- conserved

    c) Molecular O2: inlet = 250; oulet = 130 mol; consumed = 120 mol. Thus, I = O + C

     d) H2O: inlet = 0; oulet = 120 mol; consumed = 0

      e) atomic hydrogen: inlet = 100 x 4 = 400; oulet: 40x4 + 120 x 2 = 400 --- conserved

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