Felder, Rousseau, Bullard, Elementary Principles of Chemical Processes, 4e ice A
ID: 701850 • Letter: F
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Felder, Rousseau, Bullard, Elementary Principles of Chemical Processes, 4e ice Assignment Gradebook Downloadable eTextbook nent At low to moderate pressures, the equilibrium state of the water-gas shift reaction CO + H20 CO2 H2 is approximately d by the relation yon.yin = K,.(T) = 0.0247 expl402UT(K where T is the reactor temperature, Keq is the reaction equilibrium constant, and y is the mole fraction of species i in the reactor contents at equilibrium. The feed to a batch shift reactor contains 30.0 mol% CO, 15.0 mol% CO2, so.0 mol% H20, and the balance an inert gas. The reactor is maintained at T-823 K. Degrees of Freedom For the batch reaction as specified above, carry out a degree-of-freedom analysis. How many elemental balances may be written? 3 Policy 1 2000-2018 &Sons; InG, All RightsExplanation / Answer
The balanced reaction with ICE TABLE
CO + H2O + inert = CO2 + H2 + inert
I 0.30 0.50 0.05 0.15 0 0
C - x - x +x +x
E 0.30-x 0.50-x 0.15+x x 0.05
At equilibrium,
total moles = 0.30-x + 0.50-x + 0.15+x + x + 0.05
= 1
yCO2 = moles of CO2 /total moles = 0.15 + x
yH2 = x
yCO = 0.30 - x
yH2O = 0.50 - x
y inerts = 0.05
Equilibrium constant expression of the reaction
K = (0.15+x)(x)/(0.30-x)(0.50-x)
3.266 = (0.15x + x2) / (0.15 - 0.30x - 0.50x + x2)
(0.15x + x2) = 3.266(0.15 - 0.30x - 0.50x + x2)
0 = 0.4899 - 0.9798x - 1.633x -0.15x +3.266x2 - x2
2.266x2 2.7628x + 0.4899 = 0
x = 0.215
At equilibrium
yCO2 = 0.15 + 0.215 = 0.365
yH2 = 0.215
yCO = 0.30 - 0.215 = 0.085
yH2O = 0.50 - 0.215 = 0.285
yinerts = 0.05
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