Explain step by step as clear as possible! Thanks Antimony (Sb) is obtained by h

Question

Explain step by step as clear as possible!
Thanks Antimony (Sb) is obtained by heating pulverized stibnite (Sb2S3) with scrap iron and drawing off the molter antimony from the bottom of the reaction vessel. Suppose that 6 kg of stibnite and 2.5 kg of iron turnings are heated together to produce 2 kg of Sb metal. MW of Sb2S3, Fe, and Sb are 339.7, 55.85, and 121.8 respectively. The extent of the reaction is and the yield is O 8.2 gmol and 1/3rd X4.1 gmol and 2/3rd O 8.2 gmol and 2/3rd O 16.4 mol and 1/3rd

Explanation / Answer

Following reaction occur:

Sb2S3 + 3Fe --------->2Sb+3FeS

Data given:

Sb2S3= 6kg

So mole of Sb2S3= weight/MW=6 kg/339.7 kg/kmol=0.0177 kmol

Fe=2.5 kg

So mole of Fe=2.5/55.85=0.0447 kmol

Sb=2 kg

Sb mole=2/121.8=0.0164 kmol

Solution:

Here Sb2S3=0.0177 kmol

Fe=0.0447 kmol

Now as per stoichiometry

1 mol of Sb2S3 reacted with 3 mol of Fe to produce 2 mol of Sb and 3 mol of FeS

So if 0.0177 kmol Sb2S3 reated then we required=3*0.0177=0.0531 kmol Fe

But we have 0.0447 kmol

So limiting reactant is Fe

excess reactant is Sb2S3

So as per stoichiometry,

Sb2S3 required=0.0447/3=0.0149 kmol

Excess Sb2S3=0.0177-0.0149=0.0028 kmol=2.8 gmol

So % excess=(0.0177-0.0149)/0.0149*100=18.8%

Yield=as kg of Sb formed per kg of Sb2S3=2 kg Sb/6kgof Sb2S3=1/3

Related Questions

Navigate

• Browse (All)
• Browse E
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.