In the reaction 2N205 ? 4NO2 +02 given that the rate law is where v is the react

Question

In the reaction 2N205 ? 4NO2 +02 given that the rate law is where v is the reaction rate or reaction velocity, calculate the rate of formation of NO, if the instantaneous rate of reaction is 1.1 x 10 6 molL Insert answers in the form x.xEtx and include units (worth 20%)using the drop down menu. Background reading: the Chemguide concentration dependence page (38kB) the Chemguide orders and mechanism page (28kB) . Energy section Powerpoint lecture notes Answer: Choose... mol/L sec sec mo/L L/mol sed

Explanation / Answer

Rate law

v = k[N2O5]

Instantaneous rate of reaction = 1.1 x 10^-6 mol L-1 s-1

d[N2O5] /dt = vN2O5 = 1.1 x 10^-6 mol L-1 s-1

Relation between rate of formation of NO2 and Instantaneous rate

vN2O5 / 2 = vNO2 / 4

vNO2 = 2*vN2O5

= 2*1.1 x 10^-6 mol L-1 s-1

Rate of formation of NO2 = 2.2 x 10^-6 mol L-1 s-1

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