2. The retention times in seconds in a GLC are the following: Air, 5.6; n-Butane

Question

2. The retention times in seconds in a GLC are the following: Air, 5.6; n-Butane, 48.7; substance A. 85.4; n-Hexane, 103.0; substance B. 152.0 Which one of substances A and B is a linear alkane? 3. The unknown compounds U, and U2 were coinjected into a GLC with the homologous compound A and B, having 5 and 8 carbon atoms in their molecules, respectively. The retention times in minutes were the following: air, 0.5: compound A, 1.98; compound B, 11.7; compound U, 0.7; compound U2, 3.4. What is the carbon number of compounds U, and U2?

Explanation / Answer

SOLUTION:(3)

Retension time (tr) related to number of carbon

Log (tr) = (number of carbon ) x a + Constant

for A Number of carbon=5 tr= 1.98min and for B Number of carbon=8 tr= 11.7min

Putting value in above equation

a=0.2571 and constant = -0.9891

For U1 , calculate Number of carbon = 3

For U2 , calculate Number of carbon = 6

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