iPad 5:43 PM 13% Problem 8 Hydrochloric acid reacts with zinc metal to form zinc
ID: 703653 • Letter: I
Question
iPad 5:43 PM 13% Problem 8 Hydrochloric acid reacts with zinc metal to form zinc chloride and hydrogen gas. When 30.00 mL of 0.282 M hydrochloric acid is used to produce hydrogen gas, how many grams of zinc does it react with? Submit AnswerTries 0/S Problem 9 Consider the following reaction 4FeCl2(a?) 302(9) 2Fe203(s)4C2(9) what volume of a 0.760 M solution of FeCl2 is required to react completely with 5.95 x 1021 molecules of O2? mL Subnit Anwer Tries 0/S Problem 10 When 23.32 mL of 0.232 M silver nitrate is combined with 17.70 mL of 0.682 M potassium chloride, a precipitate forms. What is the molecular formula of the precipitate? Submit Answer Tries o/s What is the molecular formula of the limiting reactant? Sulomit Answer Tries o/5 What mass of precipitate, in g, is formed? Submit AnwerTries 0/5 What is the molecular formula of the excess reactant? Subnit Answer Tries 0/S What is the concentration, in M, of K in the solution after the reaction? Submit AnswrTries 0/s What is the concentration, in M, of in the solution after the reaction? Submit Answer Tries 0/s What is the concentration, in M, of Ag in the solution after the reaction? Sulomit Answer Tries o/5 What is the concentration, in M, of NO3 in the solution after the reaction? Submit AnswerTries O/s is discussion is closed Send FeedbackExplanation / Answer
Ans 8
The balanced reaction
Zn + 2HCl = ZnCl2 + H2
Moles of HCl = volume x molarity
= 30 mL x 1L /1000 mL x 0.282 mol/L
= 0.00846 mol
Moles of Zn required
= 1 mol Zn x 0.00846 mol HCl / 2 mol HCl
= 0.00423 mol Zn
Mass of Zn required = moles x molecular weight
= 0.00423 mol x 65.38 g/mol
= 0.277 g
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