QUESTION2 Two mole of an ideal gas with CV.m-32R and an initial state described

Question

QUESTION2 Two mole of an ideal gas with CV.m-32R and an initial state described by T 350 K and P reversible isothermal expansion until the pressure is half of its initial value. Calculate q 1.00 bar undergoes a AU for the process. All the units are in J, except for AS, which is in J/K. Please use E notation with 2 decimals, for example 41.4 is written as 4.14E1. If the answer is zero, input exact "or QUESTION3 Continue with the last question, calculate ASsurroundings and AStotal for the process if the surrounding is 350 K. All units are J/K. Please use E notation with two decimals, for example 40.2 is written as 4.02E1. If answer is zero, please enter "o" QUESTION 4 Two moles of an ideal gas with CV,m,-32R is heated from 175K to 300 K under constant volume, calculate AS (LK) enter your answer using E notation with 2 decimal, for example, 51.33 is written as 5.13E1 ,If the process is constant pressure, calculate AS (J/k) Please

Explanation / Answer

Ans 2

Work done in isothermal process

W = - nRT ln (P1/P2)

= - 2 mol x 8.314 J/mol·K x 350 K x ln [P1/(P1/2)]

= - 4033.97 J

= - 4.034E3 J

Internal energy for isothermal process

U = Cv(T2-T1) = Cv(T - T) = 0

Heat flow from the first law of thermodynamics

dU = dq + dW

dq = - dW

q = - W = - (-4.034E3 J) = 4.034E3 J

For an ideal gas, change in enthalpy H = 0

Entropy change for isothermal process

S = nR ln (P1/P2)

= 2 mol x 8.314 J/mol·K x ln [P1/(P1/2)]

= 11.525 J/K

= 1.1525E1 J/K

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