a Take Test Exam 3-CHEX O a https aketakepp?course a search Remaining Time: 2 ho

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a Take Test Exam 3-CHEX O a https aketakepp?course a search Remaining Time: 2 hours, 34 minutes, 09 seconds Question Completion Status: uestion 2 10 points Save Ans of years. It appears to be timolecular, yet shows a roduction reaction rate with an increase The reaction 2Norg)+O,()2NO(g) has been controversial for a number in temperature. This observation suggests that the following (pre-equilibrium) mechanism may describe this system Rapid pre-equilibrium (reversible, arrows not shown) N202+02 2NO Slow Determine the overall rate law for this mechanism Maving to the next question prevents changes to this answer Queston 2 of O Type here to search

Explanation / Answer

ans: R =  keff[NO]2[O2]

For the first reaction of the proposed mechanism

rate forward = rate backwards

(kf is the rate constant for forward reaction while kr is for backward reaction)

kf [NO]2 = kr [N2O2]

so  [N2O2] = (kf /kr ) [NO]2 ------------(1)

for the slow reaction which gives the overall rate of the reaction,

rate = rate of slow step = k2[N2O2][O2]

substituting for [N2O2] from (1)

rate = k 2 (k f /k r )[NO]2[O2] = keff[NO]2[O2] where keff is  k 2 (k f /k r )

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