13. Given the reaction at equilibrium: Xy(g) + 2 ½(g) (? 2xY2(g) + 80 kcal The e

Question

13. Given the reaction at equilibrium: Xy(g) + 2 ½(g) (? 2xY2(g) + 80 kcal The equilibrium point will shift to the right if the pressure is (A) increased and the temperature is increased (B) increased and the temperature is (C) decreased and the temperature is (D) decreased and the temperature is 14. For a given system at equilibrium, lowering increased decreased the temperature will always (A) increase the rate of reaction (B) increase the concentration of products (C) favor the exothermic reaction (D) favor the endothermic reaction 15. Base your answer to the following question on the following system at equilibrium: 2 C12(g) + 2 H2O(g)4 HCI(g)+ O2 AH +27 kcal. If the temperature of the system is increased at a constant pressure, the rate of the forward reaction will (A) decrease (B) increase (C) remain the same

Explanation / Answer

All of the answers are explained on basis of Le chatlers principle which states that a the reaction under equilibrium will shift in the direction which works to counteract a change that is imposed upon such a system

13A this reaction is exothermic. Thus if temprature is decreased, reaction will move towards the right to counteract this decrease in temperture by producing more heat. Pressure is directly proportional to temperature and hence increasing pressure with shift reaction more towards the right

14 C favors exothermic reaction

As explained in the previous answer, lowering temperature will favour reaction that produces mor heat ie exothermic reaction

15B increase here the delta H is positive so we can conclude that it is an endothermic reaction. For an endothermic reaction increase of temperature will favour forward reaction which causes decrease of temperature

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