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N Netflix My Cart-Relilla x.. Home . wchitaedu A ALEKS-Bethany Fry . Lex x 212L Midterm, Study Gui × × ? ? secure https://ww awhaleks.com/alekscgi/x/Isl.ee/1o uloNskr78P3jh1Q1HbBcWyp4GtU74E36QsaO3tOVD LL5vyaOzqFBov0t1 PleknaFGVT w8xx/5FZ2FsCEPII Ay3juspORRgU3h4M tua. O KINETICS AND EQUILIBRIUM Calculating equilibrium composition from an equilibrium constant Bethany Suppose a 250. mL flask is filled with 1.3 mol of OCl,, 1.2 mol of BrOCI and 1.9 mol of BrCI. The following reaction becomes possible: Br, (g) +OCI (gBrOCI(g)+BrCl(g) The equilibrium constant K for this reaction is 5.57 at the temperature of the flask Calculate the equilibrium molarity of BrOCI. Round your answer to two decimal places. Ar Explanation Check 1:20 PM 0 Type here to search 2/2018

Explanation / Answer

[OCl2] = 1.3 mol / 0.25 L = 5.2 M

[BrOCl] = 1.2 mol / 0.25 L = 4.8 M

[BrCl] = 1.9 mol / 0.25 L = 7.6 M

Br2 + OCl2 <----------> BrOCl + BrCl

I 0 5.2 4.8 7.6

C +x -x -x -x

E x (5.2-x) (4.8-x) (7.6-x)

K = [BrOCl] [BrCl] / [Br2] [OCl2] = (4.8-x) (7.6-x) / x (5.2-x) = 5.57

x2-12.4x + 35.5 = 28.97x - 5.57x2

6.57x2 - 41.37x + 35.5 = 0

x = 1.02, 5.27. x cannot be 5.27 as initial [BrOCl] is 4.8 M. So x = 1.02

Equilibrium concentration of BrOCl = 4.8 - x = 4.8 - 1.02 = 3.8 M

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