Please Show Formula and Steps Using data from Appendix D in the textbook, calcul

Question

Please Show Formula and Steps

Using data from Appendix D in the textbook, calculate [OH?] and pH for each of the following solutions.

Part A

7.0×10?2 M NaBrO.

Express your answer using two significant figures.

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Part B

Express your answer using two decimal places.

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Part C

8.3×10?2 M NaHS.

Express your answer using two significant figures.

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Part D

Express your answer using two decimal places.

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Part E

A mixture that is 0.13 M in NaNO2 and 0.23 M in Ca(NO2)2.

Express your answer using two significant figures.

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Part F

Express your answer using two decimal places.

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Explanation / Answer

Part A)

[NaBrO] = [BrO-] = 7 x 10^-2 M = 0.07 M

BrO- + H2O <==> HBrO + OH-

let x amount hyrolyzed

Kb = [HBrO][OH-]/[BrO-]

1 x 10^-14/2.0 x 10^-9 = x^2/0.07

x = [OH-] = 5.92 x 10^-4 M

Part B)

[H+] = 1 x 10^-14/5.92 x 10^-4 = 1.7 x 10^-11 M

pH = -log[H+] = 10.77

Part C)

[NaHS] = [HS-] = 8.3 x 10^-2 M = 0.083 M

HS- + H2O <==> H2S + OH-

let x amount hyrolyzed

Kb = [H2S][OH-]/[HS-]

1 x 10^-14/1.0 x 10^-7 = x^2/0.083

x = [OH-] = 9.11 x 10^-5 M

Part D)

[H+] = 1 x 10^-14/9.11 x 10^-5 = 1.1 x 10^-10 M

pH = -log[H+] = 9.96

Part E)

total [NO2-] = 0.13 + 2 x 0.23 = 0.59 M

NO2- + H2O <==> HNO2 + OH-

let x amount hyrolyzed

Kb = [HNO2][OH-]/[NO2-]

1 x 10^-14/4.0 x 10^-4 = x^2/0.59

x = [OH-] = 3.84 x 10^-6 M

Part F)

[H+] = 1 x 10^-14/3.84 x 10^-6 = 2.60 x 10^-9 M

pH = -log[H+] = 8.60

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