6. How many ml. o ra 0.465 M BaCl, soce are needed to react with 200 m ot a 0 62

Question

6. How many ml. o ra 0.465 M BaCl, soce are needed to react with 200 m ot a 0 620 M Napo, solution in the metathesis reaction h krw·Answer 3 BaCl (a)Na,PO, (a) Part III Chapter 5 (Work must be shown for all calculations!) A 9,07 k?ngot of tin requires 115 kJ of heat to raise its temperature from 35.0° C 10 895° C Calculate the specific heat of tin in units of J/g-deg. (Answer C, -0.233-deg) 2. Given the following table: Substance FeO (s) Fe,O, (s) 271.9 kJ/mol -822.2 kJ/mol a) Calculate the standard change in enthalpy ??' (in kJ) for the reaction below: b) Is the reaction exothermic or endothermie? (Answers: -556.8 kJ/mol; exothermic) 4 FeO (s) O2 (g) 2 Fe,O,(s) + ?

Explanation / Answer

Ans 6 :

We can use the formula , M1V1 / n1 = M2 V2 / n2

where M is molarity , V is volume and n is number of moles of species in the reaction

So putting all the values , we get :

(0.465 x V1) / 3 = (0.620 x 200) / 2

(0.465 x V1) = 186

V1 = 400 mL

So the volume of BaCl2 solution required will be 400 mL.

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