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Ounerwist hoted, il 2 pts. for each blank) Data, Trial 1 Data, Trial 2 3.OOM Mol

ID: 704905 • Letter: O

Question

Ounerwist hoted, il 2 pts. for each blank) Data, Trial 1 Data, Trial 2 3.OOM Molarity of HCI (M) (1pt. each): Volume of HCI (mL): Mass of Mg (gram): 20.00m Volume of gas before placing in 3u mL 34.89mL Equalization Chamber (mL) (I pt) (This value NOT used in calculations below) Volume of gas after placing in Equalization Chamber (mL): Barometric Pressure (mm Hg): Temperature (°C): Write the balanced overall equation for the reaction of magnesium and HCl to form hydrogen 732.5m rm Hg 23.2°C 32.5mmHg 23.2c gas and the magnesium salt (2pts) Caa) 0.044mol O.ODF2mo Mole of Mg reacted Mole of H2 formed (based on the stoichiometric equation for the reaction) Vapor Pressure of water fom curve in mm 2-1.329mmhg 21.329mmtg Pressure of H2 from Dalton's Law in mm: mmta 7Imm H Pressure of H2 in atm Volume of H2 in liter (Using volume measured in Equalization Chamber) Temperature in Kelvin 2q0.35K 2939K L-atm |-? L-afn Calculation of R (6 pts. each) Percent error Average R = 2.3G 90 1.29% 63

Explanation / Answer

1. The pressure you had in and outside of the tube must have been quite similar. In the first trial, the volume decreased, meaning that the pressure could have been a bit greater, causing the gas to move and be less in volume than before. However in the second trial, this behavior is shown in an opposite way, being able to deduce that the pressure could have been a bit smaller inside the tube. As the volumes do not change significantly, it's safe to assume that the pressures inside and outside were almost equal.

2. You must consider the roughest data that you have. For instance, the mass records have less significant figures, so it might be less accurate than others. On the other hand, the measurement of the final volume of your gas has a lot of significant figures, and if the error in measuring was done here, it could affect you report greatly.

3. Possible loss of gas could be observed, and an improvement could be to proceed in a way that allows the most of the volume to remain intact, thus giving a more accurate result of what you have in this experiment. Also, I don't know exactly how your other conditions were measured, but it is important to be able to maintain certain conditions, as pressure, temperature and quantities the most accurate that is possible. All this, summed with a proper handling of the instruments and good lab practices would ensure a better result, in terms of the error percentage. (Also, your error is not that significant, so you can safely assume that your procedure was done in a right way)

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