In an acidic solution, KMnO 4 forms the colorless manganous ion, Mn 2+ . In a st

Question

In an acidic solution, KMnO4 forms the colorless manganous ion, Mn2+.

In a strongly basic solution, KMnO4 forms green MnO42+

In neutral to mildly basic solution, KMnO4 forms MnO2

Please answer the following questions:

Effect of Conditions on Reduction of Permanganate lon a. Acidic Conditions 4. i. Write the balanced half-reaction equation for reduction of MnO4 in acidic solution. b. Strongly Basic Conditions i. Write the balanced half-reaction equation for reduction of MnO4 in strongly basic solution.

Explanation / Answer

In acidic medium : MnO4-+ 5e- + 8H+ - - - -> Mn+2 +4 H2O)

In neutral medium:MnO4- + 2 H2O + 3e- - - - > MnO2 + 4OH-

In acidic medium : MnO4- + e- - - - - - > MnO42-

MnO4-= +7, MnO42-= +6, Mn+2 =+2, MnO2 =+4

MnO4->MnO42->MnO2>Mn+2

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