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Question

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Explanation / Answer

A. At end point, no of moles of KHC8H4O4= no of moles Ca(OH)2

Moles of KHC8H4O4= 1.06/204.22= 0.00519 mol= no of moles Calcium hydroxide

Molarity of Ca(OH)2= Moles x1000/V= 0.00519x1000/22.8= 0.227 M

B. A/C to M1V1 =M2V2

M2 = M1V1/V2 = 0.0.227x25.2/26= 0.22M