1 pts Question 14 The complete combustion of 1 mole of nitrobenzene, C6H5NO2, in

Question

1 pts Question 14 The complete combustion of 1 mole of nitrobenzene, C6H5NO2, in a bomb calorimeter liberates 3088 kJ of heat and increases the temperature of the calorimeter assembly by 140.0°C. What is the heat capacity of this bomb calorimeter? ? 1.25k//oC O 4.53 kJ/ oC O 22.1kJ/°C O 432 kJ/C O 43.1kJ/ 1 pts D Question 15 The complete combustion of propane, c3He (g), is xepresented by the equation: + 5 02 (g) 3 CO2 (g) 4 H20 (1) 'sø--2220 kJ + ???? (g) How much Heat is evolved in the complete combustion of 2.50 g C3HB (G)2 O 245 kJ O 50.4 k O 126 k O 5.56 kJ O 2.22 kJ

Explanation / Answer

14'. Heat liberated by combustion = heat gain by calorimeter .

Heat capacity = heat absorbed or liberated ÷ change in temperature .

Heat capacity = 3088kJ /140°C = 22.1 kJ/°C .

Hence option (C) is correct , 22.1 kJ/°C .

15 . Moles in 2.50 g of propane = 2.50g/44g/mol = .0568 moles .

As 1 mole produces. = 2220 kJ heat

Then 0.0568 mole will produce = 2220 × 0.0568 = 126 kJ .

Option (C) is correct .

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