19. DISCUSSION From the change in the P2Os trap mass before and after reaction,

Question

19. DISCUSSION From the change in the P2Os trap mass before and after reaction, determine the mass of H2O produced by combustion of your catechol sample. Be careful to use the change in mass of each trap for just before, and just after, the catechol sample is combusted mass of H20 Similarly, determine the mass of CO2 produced from the mass change in the NaOH trap after combustion of catechol mass of co Convert the above masses into the number of moles of H20 and CO2 produced from your catechol sample moles of H20 moles moles of Co2 moles From the number of moles of H20 and CO2 produced, determine the number of moles of H atoms and C atoms in the catechol sample and enter below moles of H atoms moles moles of C atoms moles From the above and the atomic masses of the elements, determine the mass of H and C in your sample mass of H atoms mass of C atoms

Explanation / Answer

In question, Combustion of catechol give H2O and CO2 and both are trap via P2O5 and NaOH respectively.

Now reaction for combustion if catechol is

C6H6O2 + 13/2 O2 ------> 6CO2 + 3H2O

I am doing for unknown catechol

Mass of H2O = diff. in P2O5 =46.433- 38.295 = 8.138g

Mass of CO2 = Diff. in NaOH = 69.848 - 34.085 = 35.763g

Moles of H2O = mass of H2O /molar mass of H2O

= 8.138/18 = 0.45211 moles

Moles of CO2 = Mass of CO2/ malar mass of CO2

= 35.763/44 = 0.8127 moles

Moles of H atom = moles of H2O ×2/18 = 0.45211× 2/18

= 0.05023 moles of H atom

Moles of C atom = moles of CO2 × 12/44 = 0.8127× 12/44

= 0.2216 moles of C atom

Mass of H atom = moles of H atom × 1

0.05023 × 1 = 0.05023 g

Mass of C atom = moles of C atom × 12

0.2216 × 12 = 2.6600g

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