E 7/16/2018 1) Convert each of the following values to scientific notation. (1 p

Question

E 7/16/2018 1) Convert each of the following values to scientific notation. (1 point) a. 0.00010 b. 4500 c. 90,100,000 d. 0.0000079 Determine the number of the significant figures in the following. (1 point) a. 1.48 x 10-2 2) b. 156.0 c. 0.04350 d. 70.25 3) Esgpress he answer to the folowing calculations with he proper number of sgain r to the following calculations with the proper number of significant numbers and units. (1.5 points) a. (0.25 m/s) x (45.77 s) +5.0 m 2.523 lb b. (62.9 gal-58.9 gal)

Explanation / Answer

Ans1. a) 1.0 x 10-4

b) 4.5 x 103

c) 9.01 x 107

d) 7.9 x 10-6

Ans2. a) 3 significant figure (1.48 are significant)

b) 4 significant figures (156.0 are significant)

C) 4 significant figures ( 4350 are significant)

d) 4 significant figure ( 70.25 are significant)

Ans3. a) According to BODMAS, we should first multiply and then add:

( 0.25m/s x 45.77 s ) + 5.0m

= 11.4425m + 5.0m

= 16.4425m

The final result is 16.4m ( as the least count is 1 digit after decimal)

There are 3 significant figures.

b) 1lb = 0.12 gal

(62.9 gal -58.9 gal) = 4.0 gal

Now, 2.523 lb ÷ 4.0 gal

= 2.523 x0.12 gal ÷ 4.0 gal

= 0.076 gal

= 0.1 gal (2 significant figures)

Ans 4. a) 75.5 km

= 75.5 x 1000 m

= 75500m (3 significant figures)

b) 25.7 g

= 25.7 x 1000 mg

= 25700 mg (3 significant figures)

C) 0.516L

= 0.516 x 10dL

= 5.16 dL (3 significant figures)

d) 22.4 L

= 22.4 x 1.057 qt

= 23.6768 qt (6 significant figures)

= 23.7 qt (3 significant figures)

Ans5. a) Homogeneous mixture

b) pure substance

c) pure substance

d) heterogeneous mixture

Ans 6) 77k = -196.15? = -321.07 F

Ans 7. a) physical property

b) chemical property

C) physical property

d) physical property

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