In this lab, sometimes we use benzyltriphenylphosphonium bromide instead of the

Question

In this lab, sometimes we use benzyltriphenylphosphonium bromide instead of the chloride because of availability. Using the following atomic weights, what is the formula weight of benzyltriphenylphosphonium bromide? Give a whole number answer. C 12, H-1, 0: 16, N-14, P-31, Br: 80, Cl- 35.5 Answer Using the formula weight of benzyltriphenylphosphonium bromide that you calculated in the previous question, presuming you used 20 mmol of benzyltriphenylphosphonium bromide, how many grams (round up to the nearest tenth) of this substance will we use in this experiment if it is used instead of the chloride? Answer

Explanation / Answer

benzytriphenylphosphonium bromide : C25H22BrP

formula weight = (25*At.wt of C + 22*At.wt of H+1*At.wt of Br+1*At.wt of P)

formula weight = (25*12+22*1+1*80+1*31)

                       = 433 g/mol

No of mol of C25H22BrP = w/Mwt

     20*10^-3 = w/433

w = weight of C25H22BrP = 8.66 g

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