1. In class today, two students prepared a 0.290 M solution by dissolving 49.63
ID: 706948 • Letter: 1
Question
1. In class today, two students prepared a 0.290 M solution by dissolving 49.63 g of sucrose (MW - 342.3 g/mol) in distilled water and diluting to the mark with distilled water using 500.0 mL volumetric flask. Another student measured the density of the solution and found it to be 1.030g/ml. Based on the information provided, calculate the molality of this solution. 2. In class today, two students prepared a 0.350 m solution by dissolving 47.92 g of sucrose (MW 342.3 g/mol) in 400.0 g of distilled water. Another student measured the density of the solution and found the density to be 1.037 g/ml. Based on the information provided, calculate the molarity of this solution.Explanation / Answer
Ans 1 :
Density = mass / volume
volume of solution = 500 mL = 0.500 L
putting all the values :
1.030 = m / 0.500
m = 0.515 kg
or 515 grams
Mass of solvent = mass of solution - mass of solute
= 515 - 49.63
= 465.37 g
or 0.46537 kg
number of moles of sucrose = 49.63 / 342.3 = 0.145 moles
Molality = number of moles of solute / mass of solvent in kg
= 0.145 / 0.46537
= 0.312 m
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