Given the rate equation: Rate= k[X] 2 [Y] 3 (where X and Y are two reactants), w

Question

Given the rate equation: Rate= k[X]2[Y]3 (where X and Y are two reactants), what are the units of the rate constant, k?

Ms-1

M2s-1

M3s-1

s-1

M-1s-1

M-2s-1

M-3s-1

None of the above

(25 of 27)

Given the rate equation: Rate= k[X][Y]3 (where X and Y are two reactants), what are the units of the rate constant, k?

Ms-1

M2s-1

M3s-1

s-1

M-1s-1

M-2s-1

M-3s-1

None of the above

If you double a particular reactant concentration between two otherwise identical kinetic runs and you see that his causes an eight-fold increase in reaction rate, what is the order with respect to that reactant?

Zero

One

Two

Three

Four

Eight

Sixteen

Thirty Two

Explanation / Answer

Ans 1 : None of the above

The order of reaction seems ( 3 + 2 ) = 5 here.

So for the units of rate constant : (M/s) x (1 / M5)

= M-4s-1

Ans : 25 of 27 : M-3 s-1

Here the order of reaction is (1+3 ) = 4

So units of rate constant = (M / s) x ( 1 / M4)

= M-3s-1

Ans : Eight

When the concentration of a reactant is doubled , and the reaction rate increases by eight times , the order with respect to that reactant is 3.

R = [X]n

8R = [X]n

n = 3

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